[ofa-general] question about partitioning IB networks

[Meyer, Donald J]

Hal,

If you would like to use my example configuration in the man page (the one with realistic GUID's) please feel free to do so.  The GUID's are all imaginary but realistic.

Are you sure the default partition should be "Default=0x7fff,ipoib,rate=7:ALL,SELF=full;" and not "Default=0x7fff:SELF=full,ALL=limited;"?

The second version forces both known and unknown CA's to be unable to reach any CA but the sm except via their own partition.  It also seems to me that the first version bypasses partitioning by allowing CA's to use the default partition to reach other CA's not in the same partition.

Also, if you would like, I would be happy to work on a version of the man page where I would try to possibly explain a bit more and have more complete examples.

Thanks,
Don Meyer
Senior Network/System Engineer/Programmer
US+ (253) 371-9532 iNet 8-371-9532
*Other names and brands may be claimed as the property of others
________________________________
From: Hal Rosenstock [mailto:hal.rosenstock at gmail.com]
Sent: Thursday, September 03, 2009 6:46 AM
To: kliteyn at dev.mellanox.co.il
Cc: Meyer, Donald J; general at lists.openfabrics.org
Subject: Re: [ofa-general] question about partitioning IB networks


On Thu, Sep 3, 2009 at 9:43 AM, Yevgeny Kliteynik <kliteyn at dev.mellanox.co.il<mailto:kliteyn at dev.mellanox.co.il>> wrote:
Hal Rosenstock wrote:

 On Mon, Aug 31, 2009 at 3:29 PM, Meyer, Donald J <donald.j.meyer at intel.com<mailto:donald.j.meyer at intel.com> <mailto:donald.j.meyer at intel.com<mailto:donald.j.meyer at intel.com>>> wrote:
...
...

   Just as a sanity check, my interpretation so far is that my network
   should have a partition configuration file similar to the following.
    Can anyone tell me if I have this correct?  In this example
   configuration, I am trying to create two partitions.  One with rack
   one and two, the other with rack three and four:


   #Default partition (for SM control of the CA's)

   Default=0x7fff,ipoib,rate=7:ALL=limited;

Default=0x7fff,ipoib,rate=7:ALL,SELF=full;

   #rack1

   rack1=0x111,ipoib,rate=7,defmember=full:<GUID_list>;

   #rack2

   rack2=0x111,ipoib,rate=7,defmember=full:<GUID_list>;

   #rack3

   rack3=0x112,ipoib,rate=7,defmember=full:<GUID_list>;

   #rack4

   rack4=0x112,ipoib,rate=7,defmember=full:<GUID_list>;

I've never done it this way but it does look like the partition create code will detect the duplicated partitions (0x111 and 0x112) and merge ports from rack2 with rack1 and rack4 with rack3.

It will.
Note that partition names are meaningless in terms of IB management.
Basically they are used just for logging. The only real partition ID
is its pkey.

The low 7 bits (without membership bit) of pkey denotes partition.

-- Hal


-- Yevgeny
-- Hal


   *Thanks,*

   *Don Meyer*

   /Senior Network/System Engineer/Programmer/

   US+ (253) 371-9532 iNet 8-371-9532

   /*Other names and brands may be claimed as the property of others/



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